仅供参考，若有可改进之处，欢迎一起交流！
#include<iostream>
using namespace std;
//参数x表示开始元素的下标，m,n用于确定4条边尽头。
//a,b则用于判断是否可进行螺旋。p为二维数组。
void lx(int x,int m, int n, int a, int b, int **p);
int main()
{
//输入行列
int m = 0, n = 0;
cin >> m >> n;
int **a = new int*[m];
for (int i = 0; i < m; ++i)
a[i] = new int[n];
a[0][0] = 1;
//调用lx函数
lx(0,m,n,m,n,a);
//输出螺旋数组
for (int i = 0; i < m; ++i)
{
for (int j = 0; j < n; ++j)
cout << a[i][j] << ' ';
cout << endl;
}
//别忘了删动态内存
for (int i = 0; i < m; ++i)
delete []a[i];
delete[]a;
}
void lx(int x ,int m, int n,int a,int b,int **p)
{
//如果x不为0，则首元素的值为前一个元素值加一。
if (x)
p[x][x] = p[x][x - 1] + 1;
//完成四条边的赋值
for (int i = x+1; i < n; ++i)
p[x][i] = p[x][i - 1] + 1;
for (int j = x+1; j < m; ++j)
p[j][n - 1] = p[j - 1][n - 1] + 1;
if(a>1)
for (int i = n - 2; i >= x; --i)
p[m - 1][i] = p[m - 1][i + 1] + 1;
if(b>1)
for (int j = m - 2; j >= x+1; --j)
p[j][x] = p[j + 1][x] + 1;
//判断是否符合螺旋条件，从而判断是否调用lx函数
if ((a - 2 > 0) && (b - 2 > 0))
lx(x + 1,m - 1, n - 1,a-2,b-2, p);
}
调试
7 8
1 2 3 4 5 6 7 8
26 27 28 29 30 31 32 9
25 44 45 46 47 48 33 10
24 43 54 55 56 49 34 11
23 42 53 52 51 50 35 12
22 41 40 39 38 37 36 13
21 20 19 18 17 16 15 14
知识点扩展：
c++ 螺旋数递归实现
void printValue(int head,int x,int y,int n)
{
int NextHead = head + 4*n -4;
head = head -1;
if(x==n)
{
cout << (n+y-1)+head <<" ";
if(!head) cout<<endl;
}
else if(y == 1)
{
cout<< x + head<<" ";
}
else if(x==1)
{
cout << (4*n-2)-y +head<< " ";
}
else if(y==n)
{
cout << 3*n-1-x + head << " ";
}
else
{
printValue(NextHead,x-1,y-1,n-2);
}
}
void SpiralNumber(int n)
{
for (int y = 1;y<=n;y++)
{
for (int x = 1;x<=n;x++)
{
printValue(1,x,y,n);
}
}
}
